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NJ88C25 Просмотр технического описания (PDF) - Zarlink Semiconductor Inc

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NJ88C25 Datasheet PDF : 8 Pages
1 2 3 4 5 6 7 8
NJ88C25
2·0
VDD = 5V
OSC IN, FIN = 0V TO 5V SQUARE WAVE
1·5
OSC IN
1·0
FIN
0·5
TOTAL SUPPLY CURRENT IS
THE SUM OF THAT DUE TO FIN
AND OSC IN
12
3 4 5 6 7 8 9 10
INPUT FREQUENCY (MHz)
Fig. 3 Typical supply current v. input frequency
PROGRAMMING
Reference Divider Chain
The comparison frequency depends upon the crystal
oscillator frequency and the division ratio of th ‘R’ counter,
which can be programmed in the range 3 to 2047, and a fixed
divide by two stage.
R = fosc
23fcomp
where fosc = oscillator frequency,
fcomp = comparison frequency,
R = ‘R’ counter ratio
For example, where the crystal frequency = 10MHz and a
channel spacing comparison frequency of 12·5kHz is required,
R=
107
= 400
2312·53103
Thus, the ‘R’ register would be programmed to 400 expressed
in binary. The total division ratio would then be 23400 = 800
since the total division ratio of the ‘R’ counter plus the 42 stage
is from 6 to 4094 in steps of 2.
VCO Divider Chain
The synthesised frequency of the voltage controlled oscillator
(VCO) will depend on the division ratios of the ‘M’ and ‘A’
counters, the ratio of the external two-modulus prescaler
(P/P11)and the comparison frequency .
8
VDD = 5V
7
FIN = LOW FREQUENCY
0V TO 5V SQUARE WAVE
6
5
10MHz
4
3
1MHz
2
1
0·2 0·4 0·6 0·8 1·0 1·2 1·4 1·6
INPUT LEVEL (V RMS)
Fig. 4 Typical supply current v. input level, OSC IN
The division ratio N = MP1A,
where M is the ratio of the ‘M’ counter in the range 8 to 1023
and A is the ratio of the ‘A’ counter in the range 0 to 127.
Note that M>A and
N
=
fVCO
fcomp
For example, if the desired VCO frequency = 275MHz, the
comparison frequency is 12·5kHz and a two-modulus prescaler
of 464/65 is being used, then
N = 2753106 = 223103
12·53103
Now, N = MP1A, which can be rearranged as N/P = M1A/P.
In our example we have P = 64, therefore
223103=
64
M1
A
64
such that M = 343 and A /64 = 0·75.
Now, M is programmed to the integer part = 343 and A is
programmed to the fractional part364 i.e., A = 0·75364 = 48.
NB The minimum ratio N that can be used is P 22P (=4032 in
our example) for all contiguous channels to be available.
To check: N = 343364148 = 22000, which is the required
division ratio and is greater than 4032 ( = P 22P ).
CLOCK
tCH
tCL
ENABLE
tEH
tES
tEH
tES
tDS
tDH
DATA
Fig. 5 Timing diagram showing timing periods required for correct operation
4

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