Philips Semiconductors
30 Mbits/s up to 1.25 Gbits/s laser drivers
Product specification
TZA3047A; TZA3047B
SYMBOL
PARAMETER
CONDITIONS
MIN.
TYP.
MAX. UNIT
Alarm operating current: pins MAXOP and ALOP
Vref(MAXOP)
reference voltage on
pin MAXOP
IMAXOP = 10 to 200 µA
NMAXOP
VD(ALOP)L
ratio of Ioper(alarm) and
IMAXOP
drain voltage at active
alarm
Ioper(alarm) = 7.5 to 150 mA
VCCO = 3.3 V
VCCO = 5.0 V
IALOP = 500 µA
1.15 1.2
700 800
750 850
0
−
1.25 V
900
950
0.4 V
Alarm monitor current: pins MAXMON and ALMON
Vref(MAXMON) reference voltage on
pin MAXMON
IMAXMON = 10 to 200 µA
NMAXMON
VD(ALMON)L
ratio of IMON(alarm) and
IMAXMON
drain voltage at active
alarm
IMON(alarm) = 150 to 3000 µA
IALMON = 500 µA
1.15 1.2
10
15
0
−
1.25 V
20
0.4 V
Reference block: pins RREF and VTEMP
VRREF
VVTEMP
reference voltage
temperature dependent
voltage
RRREF = 10 kΩ (1%);
CRREF < 100 pF
Tj = 25 °C; CVTEMP < 2 nF;
note 5
1.15 1.20
1.15 1.20
1.25 V
1.25 V
TCVTEMP
temperature coefficient of Tj = −25 to +125 °C; note 5
−
−2.2
VVTEMP
Isource(VTEMP) source current of
pin VTEMP
−
−
−
mV/K
−1
mA
Isink(VTEMP)
sink current of pin VTEMP
1
−
−
mA
Notes
1. The total power dissipation Ptot is calculated with VBIAS = VCCO = 3.3 V and IBIAS = 20 mA. In the application VBIAS
will be VCCO minus the laser diode voltage which results in a lower total power dissipation.
2. The specification of the offset voltage is guaranteed by design.
3. Any (AVR, ER) setting needs to respect 50 µA < IMON < 2 500 µA. Therefore, for large ER settings,
minimum/maximum AVR cannot be reached.
4. The relation between the sink current Io(LA) and the modulation current Imod is: lo(LA) = Imod × 1----0---0-----1+---0--Z--0--L---(--L--A----) where
ZL(LA) is the external load on pin LA. The voltage on pin MODIN programmes the modulation current Imod. This current
is divided between ZL(LA) and the 100 Ω internal resistor connected to pins LA. When the modulation current is
programmed to 100 mA, a typical ZL(LA) of 25 Ω will result in an Io(LA) current of 80 mA, while 20 mA flows via the
internal resistor. This corresponds to a voltage swing of 2 V on the real application load.
5. VVTEMP = 1.31 + TCVTEMP × Tj and Tj = Tamb + Ptot × Rth(j-a).
2003 Jun 05
13